3x^2+2x=1240

Solution for 3x^2+2x=1240 equation:

3x^2+2x=1240

We move all terms to the left:

3x^2+2x-(1240)=0

a = 3; b = 2; c = -1240;
Δ = b2-4ac
Δ = 22-4·3·(-1240)
Δ = 14884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{14884}=122$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-122}{2*3}=\frac{-124}{6}
=-20+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+122}{2*3}=\frac{120}{6}
=20
$